# Quantitative Aptitude Questions Daily Quiz Day – 67

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119 Dear Aspirants, Our SSC Crackers team is providing a new series of Quantitative Aptitude Questions for Upcoming Exam so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.

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1) If P = (√7 – √6)/(√7 + √6), then what is the value of P + (1/P)?

(a) 12

(b) 13

(c) 24

(d) 26

2) Which value among 3200, 2300 and 7100 is the largest?

(a) 3200

(b) 2300

(c) 7100

(d) All are equal

3) What is the value of 32 + 72 + 112 + 132 + 172 – 12 – 52 – 92 – 112 – 152?

(a) 5

(b) 72

(c) 92

(d) 184

4) (a) 0.3

(b) 0.4

(c) 0.7

(d) 1.1

5) How many positive factors of 40 are there?

(a) 3

(b) 4

(c) 6

(d) 8

6) A is 20% more efficient than B. If B alone can complete a piece of work in 12 days, then A alone can complete the same work in how many days?

(a) 10

(b) 12

(c) 14

(d) 16

7) A and B together can complete a work in 10 days. They started together but A left after 2 days and the remaining work was completed by B in 12 days. In how many days can A complete the entire work while working alone?

(a) 15

(b) 20

(c) 30

(d) 45

8) What will be the net discount (in percentage) after two successive discounts of 50% and 50%?

(a) 85

(b) 75

(c) 100

(d) 95

9) An article is sold for Rs 5330 after a discount of 18%. What is the marked price (in Rs) of the article?

(a) 6250

(b) 6450

(c) 6800

(d) 6500

10) Raman, Rohit and Raja are partners and invest in a business. Raman invests 1/4th of total and Rohit invest 1/3th of the total. What is the ratio of profit of Raman, Rohit and Raja respectively?

(a) 4 : 3 : 1

(b) 3 : 4 : 4

(c) 3 : 4 : 5

(d) 4 : 3 : 5  (3² – 1²) + (7² – 5²)+ (11² – 9²) + (13² – 11²) + (17² – 15²)

= 4 × 2 + 12 × 2+ 20 × 2 + 24 × 2 + 32 × 2

= 8 + 24 + 40 + 48 + 64

= 184 = 0.7 – 0.4 = 0.3

positive factors are 2,1,4,5,8,10,20 and 40

Total factors = 8.

If A is 20% more efficient then it will take  t/1.2  time (where t is time taken by B)

Hence time taken by A  = 12/1.2 ⇒ 10 days

Both do the given work in 10 day

If they work together for 2 days they will finish 1/5th of the given work.

Remaining work = 4/5 th of given work

B does 4/5 of total work = 12 days

Time required for total work = (12×5)/4

= 15 days

1/A + 1/B = 1/30; 1/A = 1/30 –  1/15

1/A = (3-2)/30 = A = 30 days Total discount = 100 – 25 = 75%

After 18 discount on MP

82% MP → 5330

82/100 MP  → 5330

MP = (5330 × 100)/82

= 6500